我最近瀏覽中國局域網，看見不少機構在販售記憶藝術論壇上的內容。我決定免費公開出來我的中文版3位數系統和2卡系統的想法。
主要原因是我最喜歡的youtuber導師ICT，他在2023年聖誕節免費公開了自己的私人輔導的教學視頻，原因也是因為有人私自販售他相關的課程：）
I recently browsed the Chinese LAN and saw that many organizations were selling content from the Memory Art Forum. I decided to share my ideas for the Chinese version of the 3-digit system and the 2-card system for free.
The main reason is my favorite YouTuber tutor ICT. He released his private tutoring teaching videos for free on Christmas 2023. The reason is also because some people are selling his related courses privately:)
兩位數系統使用聲音、形狀和意義。
但三位數制和四位數制很難做到這一點。在這種情況下，需要升級版本的聲音。
英語：
元音和輔音
中文：
聲母和韻母
將數字轉換成特定的字母音節，並將其拼寫成漢語詞彙。然後將漢字詞彙轉換為圖片代碼。
》漢字量資料來自網路
拼音系統是由漢字數量最多的十個聲母組成的，以下是漢化的過程。
其他首字母不能省略，也不能寫成多組字。以下是漢字數量最多的聲母。
過濾掉剩下的4個聲母
漢字數量很少，不需要添加。它用於輔助目的。
The two-digit system uses sound, shape, and meaning.
However, it is difficult for the three-digit system and the four-digit system to do this. In this case, an upgraded version of the sound is needed.
English:
vowels and consonants
Chinese:
initials and finals
Convert numbers into specific letter syllables and spell them into Chinese vocabulary. Then the Chinese character vocabulary is converted into a picture code.
"Chinese character volume data comes from the Internet
The pinyin system is composed of the ten initial consonants with the largest number of Chinese characters. The following is the process of Chineseization.
Other initial Chinese characters cannot be omitted or written in multiple groups of words. The following are the initial consonants with the largest number of Chinese characters.
Filter out the remaining 4 initial consonants
The amount of Chinese characters is minimal and does not need to be added. It is used for auxiliary purposes.
A(71)
E(48)
O(14)
R(99)
In the end, ten vowels were screened out and assigned to vowels 0-9 according to the pictograms.
最终筛选出10个元音，根据象形图分配到0-9元音。
C(CH)(414)
H(323)
J(523)
L(472)
D(326)
Q(318)
S(SH)(465)
X(390)
Y(571)
Z(ZH)(546)
The selected initial consonants are used for the second time when the first initial consonant cannot form a word.
当第一个声母不能形成单词时，第二次使用所选的声母。
K(197)
T(264)
G(301)
N(161)
F(204)
M(280)
P(224)
W(203)
B(313)
"
初代版本·拼讀系統（ben system 華語化）
pinyin system (ben system Chinese)
| 0 | D/P | D/P | u |
|---|---|---|---|
| 1 | L/R | L/R | a |
| 2 | Z(zh)/N | Z(zh)/N | e |
| 3 | C(ch)/M | C(ch)/M | i |
| 4 | Y/F | Y/F | o |
| 5 | S(sh)/W | S(sh)/W | u |
| 6 | H/B | H/B | a |
| 7 | J/T | J/T | e |
| 8 | X/K | X/K | i |
| 9 | Q/G | Q/G | o |
百位：第一聲母
Hundreds: First initial consonant
0 = D / P
1 = L / R
2 = Z(zh) / N
3 = C(ch) / M
4 = Y / F
5 = S(sh) / W
6 = H / B
7 = J / T
8 = X / K
9 = Q / G
十位：第二聲母
Tenth place: Second initial consonant
0 = D / P
1 = L / R
2 = Z(zh) / N
3 = C(ch) / M
4 = Y / F
5 = S(sh) / W
6 = H / B
7 = J / T
8 = X / K
9 = Q / G
十位：韻母
Tenth place: vowels
0 = u
1 = a
2 = e
3 = i
4 = o
5 = u
6 = a
7 = e
8 = i
9 = o
示例
Example
| 100 | 朗读机 | LangDUji |
|---|---|---|
| 101 | 卤蛋 | LuDAn |
| 102 | 拍立得 | paiLiDE |
| 103 | 炉鼎 | LuDIng |
| 104 | 绿豆 | LvDOu |
| 105 | 伦敦塔 | LunDUnta |
| 106 | 手榴弹 | shouLiuDAn |
| 107 | 红绿灯 | hongLvDEng |
| 108 | 螺钉 | LuoDIng |
| 109 | 漏斗 | LouDOu |
| 002 | DaDingZi | 大釘子 |
|---|---|---|
| 517 | ShouLiJian | 手里剑 |
| 546 | SiYangHe | 饲养盒 |
| 791 | JinGangLang | 金刚狼 |
| 996 | QiaoQiaoBan | 蹺蹺板 |
| 618 | BoLiXin | 玻璃心 |
| 775 | JiangJieShi | 蔣介石 |
| 716 | TaLvBan | 塔綠班 |
| 245 | ZiYounvShen | 自由女神 |
| 879 | XiJinPing | 習近平 |
|---|---|---|
| 528 | WeiNiXiong | 維尼熊 |
| 723 | TiaNanMen | 天安門 |
| 781 | TanKeRen | 坦克人 |
| 964 | QiBaoFu | 起爆符 |
| 555 | WanWanWa | 灣灣蛙 |
| 345 | CaiYingWen | 蔡英文 |
| 949 | GuangFuQi | 光復旗 |
一些關於我是如何將聲母分配至0-9之間的小解答
0=D / P *D形狀圓圓的 所以分配至0 ，P也是長得像0,，只是多了條尾巴
1 = L / R * L的小寫字母l 長得像1 ，R是因為 L和R 的發音相似
2 = Z(zh) / N * Z長得像2 ，N長得像Z跌倒了的樣子
3 = C(ch) / M * C長得像鏡像的3，M 長得像 跌倒的3
4 = Y / F * Y 小寫y 個人認為長得像4，F是因為英文“four”
5 = S(sh) / W *S長得像5 ，W因為華語“五”的拼音Wu
6 = H / B *H的小寫h 像6少了腳，B的小寫b像6
7 = J / T *J長得像倒7 ， T長的像7多了個小辮子
8 = X / K *X長得像是8少了頭和腳，K也和X同樣的原因
9 = Q / G *Q的小寫q像9 ，G的小寫g也像9
漢尼斯系統 3卡2图系统
Hannes System 3 cards 2 image system
2007年，名為競技記憶的雅虎小組裡，有名叫漢尼斯的記憶選手，發表了一個全新的撲克系統叫漢尼斯系統。他是一種三卡二圖系統。和PAO系統類似。記憶一副撲克牌只需要17到18個地點。
In 2007, there was a memory player named Hannes in the Yahoo group called Competitive Memory, and he published a brand new poker system called the Hannes System. It is a 3-cards 2-picture system. Similar to the PAO system. Memorizing a deck of cards requires only 17 to 18 locations.
數字的花色轉換方式
Digital suit conversion method
（A~10）
=1 
=2 
=3 
=4
王牌的花色轉換方式
Ace’s suit switching method
honje系统版本
honje system version
（ JQK）+5
= 6 =7 =8 =9
汉尼斯系统版本
Hannes system version
（ JQK）+4
=5 =6 =7 =8
數字和王牌轉化數字
Numbers and Aces Convert Numbers
10轉化為0，A轉化為1，其餘不變
10 is converted to 0, A is converted to 1, and the rest remain unchanged.
王牌轉化數字
Ace Conversion Numbers
honje系統版本
honje system version
J=7
Q=9
K=8
漢尼斯系統版本
Hannes system version
J=9
Q=1
K=7
中國流行版本
Popular version in China
J=1
Q=2
K=3
王牌的轉化方式，根據自己個人喜好來轉化就好。
漢尼斯系統呢因為要做到直接用三位數係統來記憶撲克的關係，所以必須橫的看才能做到這一點。首先來看下，一卡系統的三張撲克牌，
Ace’s transformation method can be transformed according to your own personal preferences.
The Hannes system needs to directly use the three-digit system to memorize poker relationships, so it must be viewed horizontally to do this. First, let’s take a look at the 3-card playing cards of the 1-card system.
K34
從上往下轉換
Convert from top to bottom
K=8
=7
示例
Example
K=87
3
=34
4
=41
從下往上轉換
Convert from bottom to top
K=3
=7
示例
Example
K=73
3=43
4=14
漢尼斯系統示例
漢尼斯系統版
Hannes system example
Hannes system version
K34 =734
=613
honje系统版
honje system version
K34 =834
=741
834 =834
=241
KJQ=879
=789
879=879
=234
我覺得這款系統非常適合一些已經熟練3位數係統但是又不想擴展至2卡系統的記憶選手。
你可以直接在撲克上使用1000個3位數係統編碼圖像
數字和王牌：10X10X10=1000圖像
花色：8X8X8=512圖像
你記憶一副牌
只需要35個3位數係統編碼圖像
只需要17-18個地點
當然你也可以選擇 13個地點，也就是一個地點上放6張撲克牌。這操作似乎很考驗你的技術水平。
I think this system is very suitable for some memory players who are already proficient in the 3-digit system but don’t want to expand to the 2-card system.
You can encode images directly on poker using the 1000 3-digit system
Numbers and Aces: 10X10X10=1000 images
Suit cards: 8X8X8=512 images
You memorize playing cards once
Only 35 3-digit system encoding images are required
Only 17-18 locations are needed
Of course, you can also choose 13 locations, that is, put 6 playing cards on one location. This operation seems to test your technical level.
扬·佐恩 系统 4卡3图系统
Jan Zoń System 4 cards 3 image system
二卡系統
二卡系統一般指的是兩張牌一張圖像，目前據我所知二卡系統的存在，一共有四種的形式。
The 2 cards system generally refers to 2 cards and one image. As far as I know, there are four forms of the 2 cards system.
第一種
simon system （西蒙系統）
這套二卡系統是最簡單 最容易學會的。
西蒙系統的撲克編碼圖像量為2704個
完全是由四位數編碼系統構成。不使用三位數編碼系統
This 2-card system is the simplest and easiest to learn.
The number of poker encoded images in the Simon system is 2704
It is entirely composed of a 4-digit coding system. Not using a 3-digit coding system
轉換方式（代入漢尼斯系統的轉換方式）
Conversion method (conversion method into the Hannes system)
（A~10）
=1 =2 =3 =4
（ JQK）+5
= 6 =7 =8 =9
Example
A9
→ 1293
J10→7801
710→7301
第二種
ben system （ben系統）
需要完整的三位數系統（1000）和零散的四位數系統（1704）
合計2704圖像
也可以去掉重複的編碼圖像，只製作2652個圖像
Requires complete 3-digit system (1000) and fragmented 4-digit system (1704)
Total 2704 images
You can also remove duplicate encoded images and only make 2652 images
我只做了2個版本
第一個是+16版本
第二個是+20版本
I made 2 versions
The first one is the +16 version
The second one is the +20 version
| A | B | C | D | E | F | G |
|---|---|---|---|---|---|---|
| 1600 | 480 | 480 | 144 | |||
| ben 2 cards | # + # | # + A | A + # | A + A | ||
| ben二卡 | 数字+数字 | 数字+王牌 | 王牌+数字 | 王牌+王牌 | ||
|
00（10） | 16 | 32 | 48 | D/P | |
|
01（A） | 17 | 33 | 49 | L/R | |
|
02 | 18 | 34 | 50 | Z(zh)/N | |
|
03 | 19 | 35 | 51 | C(ch)/M | |
|
04 | 20 | 36 | 52 | Y/F | |
|
05 | 21 | 37 | 53 | S(sh)/W | |
|
06 | 22 | 38 | 54 | H/B | |
|
07（J） | 23 | 39 | 55 | J/T | |
|
08（K） | 24 | 40 | 56 | X/K | |
|
09（Q） | 25 | 41 | 57 | Q/G | |
|
10 | 26 | 42 | 58 | D/P | |
|
11 | 27 | 43 | 59 | L/R | |
|
12 | 28 | 44 | 60 | Z(zh)/N | |
|
13 | 29 | 45 | 61 | C(ch)/M | |
|
14 | 30 | 46 | 62 | Y/F | |
|
15 | 31 | 47 | 63 | S(sh)/W |
| 1600 | 480 | 480 | 144 | ||
| ben 2 cards | # + # | # + A | A + # | A + A | |
| ben二卡 | 数字+数字 | 数字+王牌 | 王牌+数字 | 王牌+王牌 | |
|
00（10） | 20 | 40 | 60 | D/P |
|
01（A） | 21 | 41 | 61 | L/R |
|
02 | 22 | 42 | 62 | Z(zh)/N |
|
03 | 23 | 43 | 63 | C(ch)/M |
|
04 | 24 | 44 | 64 | Y/F |
|
05 | 25 | 45 | 65 | S(sh)/W |
|
06 | 26 | 46 | 66 | H/B |
|
07（J） | 27 | 47 | 67 | J/T |
|
08（K） | 28 | 48 | 68 | X/K |
|
09（Q） | 29 | 49 | 69 | Q/G |
|
10 | 30 | 50 | 70 | D/P |
|
11 | 31 | 51 | 71 | L/R |
|
12 | 32 | 52 | 72 | Z(zh)/N |
|
13 | 33 | 53 | 73 | C(ch)/M |
|
14 | 34 | 54 | 74 | Y/F |
|
15 | 35 | 55 | 75 | S(sh)/W |
