I have seen one memory athlete demonstrating square numbers and cube numbers. When he as about square of 87 and 76 he was able to tell in a jiffy. Also when he was given last 3 digits of a cube number, he completed remaining 3 digits and he told its cube root immediately. What memory techniques he could have used to learn these concepts.
That depends⦠you can either use memory techniques or simply concepts from mental math.
Unfortunately, āa jiffyā is not a very quantitative way of referring to things⦠letās take the mental math approach first for the 76^2 above.
Squares ending in 0 or 5 are super easy to calculate. Pick 75; since itās closer than 80. To calculate a two digit number a|b (in this case 7|5), multiply a(a+1) for the left hand side (here 7*8) and square b for the right hand side (always 25). To get from 75^2=5,625 to 76^2, you just double the number you squared (here 75*2=150 and add it on top, plus an additional 1 for 5,625+150+1=5,776
For a bit more in-depth about this approach have a look hereā¦
I donāt understand what you mean by ācompleted remaining 3 digitsā but cube roots are easier than square roots. Just search here on the forum or google āVedic math cube rootsā. Both your question have been explained before on here, so you shouldnāt have a problem finding the information using the search function.
For 2-digit squares and cubes, itās pretty easy to memorize these directly using flashcards (e.g. spaced repetition software on cram mode) Iāve done it for squares, but not for cubes. I had an Indian kid in a workshop once who knew the cubes by heart.
These days I use more advanced tool that Iām still experimenting with, but the principle is the same.
For squares, you should see some patterns in the data. For example, notice the following:
23² = 529
27² = 729
73² = 5329
77² = 5929
The squares of X, 50 ā X, 50 + X and 100 ā X all end in the same two digits.
You can also see that the squares above 90 all have an even hundreds digit, and end in the single-digit squares 81, 64, etc.:
8281
8464
8649
etc.
Youāll find many more patterns if you write out the examples and study them.
@chaitanya10 you can have a look here for the symmetry around 25.
ā¦and once youāre at 50, you got the symmetry that @Daniel_360 already mentioned. That letās you technically go all the way up to 100; however, Iād use the symmetry around 75 instead to make the calculation easier.
Alternatively, you could build your PAO system in such a way that the O is a 3-digit number that represents the square of P. In mine, for example, I have āKylie Minogue squeezing a LeMoNā
KM is 73 with a square of LMN which is 532_ and then you just append the unit digit squared (i.e., 3^2=9) to get 73^2=5,329 and thatād how you get the squares up to 100 without even calculating.
I still donāt get it⦠āis part ofā⦠what does that mean? 616 could be part of any number⦠you guys could have given him 615 or 614 instead⦠then what⦠thereās no perfect cube ending in these digits.
Did he ask you guys to use a calculator to cube a 2-digit number and then just give him the last 3 digits for him to complete?
About as impressive as listening to the radio blindfolded. Iām sure he could have tied his hands behind his back too. How does either make it more challenging to do cubes or squares? Itās one thing to do a Rubikās cube blindfolded but here I really donāt see the point⦠total gimmick.
EDIT:just watched the video below. This was done during an online presentation to ensure the other participants that he is not reading off the result from somewhere rather than an obstacle to make the exercise harder. All good then!
Learn the single digit cubes 0 through 9: 0, 1, 8, 27, 64, 125, 216, 343, 512, 729
Cubes end in the same digits as the number cubed. Exceptions are 8/2 and 7/3 where itās flipped: 8 is 2 and 2 is 8; 7 is 3 and 3 is 7.
Separate the last 3 digitsā¦
175 | 616
Find the biggest cube smaller or equal to 175 (see 1.), which is 5^3=125
Append to 5_ the corresponding unit digit for 616, which is _6 for 56
778 | 688
729 is less than 778 from 1. above for 9_
688 end in 8 which is _2 according to 2. above, so you get 92
132 | 651
125 gets you 5
append 1 to get 51
125 | 000
5_ ā 125
_0 ā 50
117 | 649
4_ ā 64
_9 ā 49
Hope that makes sense⦠you might not know why⦠but you should know how now.
I do this for calculating the square and cube of numbers with a Person / Object type method.
I have a set cast of characters that I always use for the number 00 to 99
Then I created words for the calculation results. Using a number to letter system. (I use Rhyming Letter Getters, but works same with Dominic System or Major System)
So for example 41 in my cast is David Beckham, the square of 41 is 1681 which translates as BSGB (Using the number to letter code that I use)
Then I inserted āNull lettersā and created the words āBus Globeā. Whilst a Bus Globe is not a real thing it can certainly be visualised.
So I mentally created a movie scene that links David Beckham to Bus Globe and I have now linked 41 with 1681 in a visual movie.
Using the Dominic System 41 would be DA, so that could be David Attenborough - 1681 would be ASHA - I could insert ānull lettersā and make it AStHmA - so imagining David Attenborough with Asthma Iād have a scene that would remind me of the answer to the sum.
Are you saying thatās how you do do it or how you would do it?
41^3=68,921 though and now youāre translating 5 letters? And once you get past 46, itās 6 letter translations? Isnāt it kinda difficult to find words then?
I do this for Square numbers but only as a party piece. Creating the phrases was pretty easy but the words are quite obscure. But itās a fixed list - so I only ever had to do it once.
For longer numbers (sums, codes or references) I use a Person to Person/Action/Object/Quote type method which is really effective.
I link my cast member for the number with the POAQ attributes of the answer (67 cubed - 67 is 300,773) - 67 in my cast is Stephen Hawking and then the result split into pairs gives me 30-07-63 - These relate to 3 cast members, and Iād create an image of Stephen Hawing interacting with them in normal person, action object way.
Just sticking with the āSquaresā of numbers, that sounds well and good in theory but in practice?? For example, my 99 is Nick Nolte (as I am using the Dominic System). NN squared = 9801 or NHOA. Now hereās the rub, how can I get anything for 99 (NN) from these letters when the only vowels I can use that are not already being catered for in Dominic system are the: I and U (vowels) as in Dominic system: A=1, E=5 and O=0. I have always thought the Dominic system as superior to the Major System but from the above example 99 in Major could translate into PP (Peter Pan). 9801 in Major System translates into PFST. Pea FeaST or even BFST (BeeF STew). I am beginning to believe well at least for āsquaringā and āCubingā of two digit numbers that the Major System trumps the Dominic System as you have the advantage of being able to use every vowel as a āsilent fillerā!
Or perhaps to think outside the box a little, one could use both Dominic System and Major Systems alongside one another. For example, Dominicās NN or 99 (Nick Nolte) could be enjoying a BeeF STew = 9801). Dominicās DA = 41 (David Attenborough) could be eating Hollandse Nieuwe Haring which in English is āScoused Herringsā or Dutch Food (1681). I can picture David Attenborough stuffing his face full with āScoused Herringsā, hence 41 squared = Dutch Food = 1681. In fact David Attenborough has stuffed himself so full with āScoused Herringsā (Dutch Food) that he is having an AStHmA attack bringing it full circle back to Dominic system again. LOL!
Hi Fred, I too thought the Dominic System was above the Major System. But didnāt like the fact it used vowels. Now I only ever use Rhyming Letter Getters because this system also leaves all the vowels as ānullā letters (silent fillers). Coincidentally I also have Nick Nolte in my cast list (for 00 as that becomes NN using RLGās). 9801 translates at WGNB - inserting null letters I get āWaGoN Barā.
I think mixing systems would be useful for some aspects, but I do prefer just have definitive letters for each number.