ok, so i decided to memorize the first 50 numbers in the fibinacci sequence, and this exposed a problem i’m not sure how to tackle within my system. specifically, how to compress a 19 digit number into a single pao style image. this will be a long post with lots of details…
my system is a 3-2-2-2 paoq (person, action, object, quote)
- person 000-999
action 00-99
object 00-99
quote 00-99
and a PAO for single digits 0-9
- person 0-9
action 0-9
object 0-9
so for a single locus, i can cleanly encode 9 digits 3-2-2-2 (paoq). what i’m looking for, is how to stretch out how many numbers i can encode in a single locus. i was able to stretch it to 10 digits using 3-2-2-3 (paop), and think i could further stretch it to 12 with the same idea 3-2-2-2-3 (paoqp)
but i’m not sure how to expand past that for a string of numbers say 13-19 digits long, in the same locus, preserving the numbering location of each loci… ie 37th spot is the 37th number
using fibonacci and 50 locus in a 100 loci memory palace, i was able to encode 1 to 10 digit length numbers in each locus, using the following strategy
clarifying that at each locus, the length of digits to memorize, was from 1 to 10 digits long. my loci are grouped in 10’s, so i can easily say, go to the 37th locus and recite 14930352 as the 37th fibonacci number. this is why i want to compress more numbers into a single locus
here are some of the different length numbers in fibonacci, and how i went about adjusting my system for organizing the memo:
(details on how i used my system to encode different length numbers)
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0
1 digit (person)
used the 1 digit person from single 0-9 pao
(0) -
13
2 digits (person)
used a 2 digit person from 000-999 pao, ignoring the 0 in 013… so 013, just becomes 13
(13) -
144
3 digits
used a 3 digit person from 000-999 pao
(144) -
1597
4 digits (person / object)
used a 2 digit person from 000-999 pao, ignoring the 0, and a 2 digit object
(15-97) -
10946
5 digits (person / object)
used a 3 digit person from 000-999 pao, 2 digit object
(109-46) -
121393
6 digits (pao)
used a 3 digit person, 2 digit action, 1 digit object (could have also done 2-2-2)
(121-39-3) -
1346269
7 digits (pao)
used a 3 digit person, 2 digit action, 2 digit object
(134-62-69) -
14930352
8 digits (pao / quote)
used 2 digit person, 2 digit action, 2 digit object, 2 digit quote
(14-93-03-52) -
102334155
9 digits (pao / quote)
used a 3 digit person, 2 digit action, 2 digit object, 2 digit quote
(102-33-41-55) -
7777887749
10 digits (pao / 2nd person)
used a 3 digit person, 2 digit action, 2 digit object, 3 digit person
(777-78-87-749) -
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this brought me to the 50th number of fibonacci, so it ultimately worked for my desired purpose. and this was the first time that i really experimented with using my encoding system to account for all kinds of number lengths
and as you can see, i switched around how i used the system in different ways to get to the desired number length to memorize while keeping the imagery easy to recall
but here’s my dilema…
i want to memorize this power of 2 table…
(a 64 bit signed integer)
so cleanly, my 9 digit encoding system will work great for up to the 29th entry (536 87 09 12)
but i’m not sure how to expand my system beyond that, to allow longer numbers to be placed in a single locus… as my 9 digit system becomes tapped out.
i figured out how to do a 10 digit number in fibonacci, by replacing the the quote with another person (paop) 3-2-2-3, and i suppose i could stretch it further by going (paoqp) and getting 3-2-2-2-3 for 12 numbers… but how can i stretch the imagination and imagery to get those final numbers which are 19 digits long… including the inevitable lengths of 13, 14, 15, 16, 17, 18 as well
has anyone pushed their system to allow the encoding of numbers this large with a single locus per number? how does that look?
what a paoq/paoq?
a person… doing an action, with an object, saying a quote, to another person… doing an action, with an object, saying another quote, and still being 1 digit shy?
- the biggest number i’ll need for the last locus is 19 digits long:
- 9 223 372 036 854 775 808
but again, i’d like to be able to go to say the 50th power of 2, stored at the 50th locus, and recite the 16 digit number: 1 125 899 906 842 624, which is well beyond the normal scope of my 9 digit system.
even stretching my system to 12 digits, i’d only get to the 39th of 64 numbers before the length exceeds my encoding.
any ideas on compressing these numbers?
fibonacci pic for reference:



