When in two numbers 0 is present.
Example - 807^2
For doing this mentally ,
First part - square first no
Middle part - multiply first and last digit and
double it
Last part - square last no.
Ans-. 64 | 8 * 7 * 2 | 49
64 | 112 | 49
651249 (middle and last part contain 2 digits because after digit 0 two digit is present and 0 itself)
wow this is awsome!!! I am also into math, but more to the theoretical side, such as reimann zeta function ( how if it is true - I am sure it is XD, the product of all natural numbers or prime numbers will be a finite answer) which I am focusing right now, imagine cracking the prime number code, and make everyone pay for a new online security XDDDDD
ohh and you can use this technic for all x^n then you just have to know the binomial expansion of (a+b)^n which can be easily done with pascal’s triangle rule
I am well familiar with its name in Hindi; however, this is the English speaking section of the forum. If I post in Non-English Forums I’ll make sure to translate it. Duplex is also the name Bharati Krishna Tirtha called it in English.
That is not true. You can of course use double-digits instead of single-digits in duplex, which is exactly what I have done in my above example.