If you allow for duplicates, there are 52 options for card one (every card in the deck) and 52 options for card two (every card in the deck).
52 x 52 = 2704.
If you don’t allow for duplicates there are 2652 total combinations. Found by taking the 52 options for card one (all cards in the deck), and 51 options for card two (all cards except the card that was used for card one).
52 x 51 = 2652
haha, there’s nothing wrong with ideas! If this system you’ve proposed makes sense to you and you can quickly convert that data and memorize with it at a speed you’re happy with, then embrace it and use it!
Here’s a couple links explaining how you arrive at the 1352 total, by cutting the total elements needed for the pair combos via the 2-block system: