Hi Tiger. Great to see you back!
You and I have discussed division in the past a lost. Starting in 2017.
I use a lot of techniques and here is a list of them:
Yes, in two steps usually.
I think I wrote about it in the past, but could not find it, so let’s do it again.
Let’s divide 1000 by 323.
Here goes. 1000/333 = 3.
323 is lower, so try 3 times.
Now let’s find the remainder in two steps.
1: 3 times 300 is 900. Subtract from 1000 to get 100.
2: 23 times 3 is 69. Subtract from 100 = 31.
If we divide by a number close to a multiple of 100, we can do this slightly different and work with negative numbers.
Let’s divide 1000 by 378.
Here goes. 1000/333 = 3.
378 is higher, so try 2 times.
Now let’s find the remainder in two steps.
1: 2 times 300 is 600. Subtract from 1000 to get 400.
2: 78 is 22 from 100. Subtract 2 times 100 = 200 from 400 and then add 2 times 22 = 44 to get 244.
(We will get back to this remainder later.)
Let’s continue working. We now have 2R244.
Add a zero: 2440.
Try to find a multiple using 400 instead of 378.
2440 goes into 400 about 6 times or 6 time 400 is 2400 and fits in 2440.
2 steps again:
1: 2240 - 6 times 400 =2400 = 40.
2: Add 6 times 22 = 132 to get 172.
Add a zero:1720
1720 goes into 400 4 times.
1720 - 1600 = 120. 120 + 4*22 = 208
Etc, etc.
You might want to experiment with switching 2 steps. Saves one digit in short term memory.
Starting from the remainder of 244:
Instead of adding a zero, do the subtraction of the hundreds first.
But since we have not added the zero yet, the 400 is now 40
Try to find a multiple using 40.
244 goes into 40 about 6 times or 6 time 40 is 240 and fits in 244.
244 - 240 = 4.
Now add the zero. 4 => 40.
Step 2 is the same as above:
2: Add 6 times 22 = 132. Add to 40 of the previous step to get 172.
This can be done in the 323 case as well as above.
The remainder is now always 3 digits.
Subtract the hundreds first, not forgetting that 378 => 400 => 40 or that 323 => 300 => 30.
Try this on random numbers and see if it works for you.