My question is: how do you implement the PAO system in which the amt of digits in the string of numbers is not divisible by 6?
If: 12= Spiderman shooting webs
23= Tom Hanks sitting on a bench
34= Brad Pitt shooting a gun
Then what is the string 12233412?
Does that mean I need to use two loci?: The first being Spiderman sitting on a gun, the second being Spiderman shooting webs?
What is the string 1223341?
The PAO system uses a two digit system right? What do I do with a single digit at the end of a 7 digit string? (or a 13 digit, 19 digit, etc.)
What do I do if the two digits repeat?
What is 121212?
Do I picture Spiderman shooting webs three times? Three of them in a single loci?
Sorry for a jumbled post, I’m new here.

In the case of 12233412. You would need to use two loci. The first for the PAO and the second could just have spidering there.

For 1223341 you would need a system for encoding single digits as well. For example in the number shape system the number 1 usually becomes a stick.

If the digits repeat then you would treat it how you treat any other PAO, a single loci, a single image, just spiderman shooting webs. Single the P, A and O all come from spiderman it should tell you that the number was 121212
 Sorry I mean Spiderman not spidering. Stupid autocorrect
Excuse me checking the number is divisible by six is actually much faster then memorisation, don’t?
123456 divisible of 6?
mental process:
Divisible by 2, and get 61728.
6+1+7+2+8=24 and is divisible by 3.
So the statement is true.
You misunderstood my question. I was asking about what happens when the amt of digits in the string is not divisible by 6, not the value of the string itself
Thanks!
If you wanna you can put 8 digits at 1 loci too.
1 )12 23 32 12 (8 digits)
Spiderman sitting on Gun  webs (guns that is covered with webs)
2 ) 12 23 34 1 (7 digits)
Spiderman sitting on gun (bullet)
Just say gun (and don’t say bullet, imagine after looking 1 bullet without saying any thing)