Card system summary

There are lots of card systems topic in this forum, however, a few posts summarise the current system situations.

Thus, there we do not have a common consensus on the card system.

I would like to build a card system table, that everyone can easily refer to.

1-card system
Examples No. of Pegs Cards:combined Img Combined Img/Deck Decription
X1 52 1:1 52 A X can be any of collections: persons/actions/objects/extra
X2 104 2:1 26
X3 156 3:1 17
XN 52*N N:1 52/N
2-card system
Examples No. of Pegs Cards:Img Img/Deck Decription
@LociInTheSky Shadow 1326 2:1 26 block chain (stack by color)
@Zoomy 2652 2:1 26 combinations: 52*51
Location Based 676 2:1 26 location wise to identify a suit
N-card system? (no example)
Suit Rank Decomposition (SRD)
Examples No. of Pegs Cards:Combined Img Img/Deck Decription
3S3R 2261 3:2 34 3S=4^3=64; 3R=13^3=2197
2S1R-2R1S 676 3:2 34 Img1=(4^2)13=208<Img2=(13^2)4=676; both use 676 images
@zonjan 4S(2R)2 425 4:3 39 4S=4^4=256; 2R=13^2=169
Examples No. of Pegs Cards:Combined Img Combined Img/Deck Decription
PA-boost 273 2~4:1 max(26), average(20) Editted from normal PA {104}. When there is a pair of same suit: a single object is used to represent that 2 ranks notation. Total objects:{169}. No, user found. Antelex is willing to try once he can finish with cards in one minute.

Antelex had tried the concept, it works but like previous mentioned, without seeing all the cards, the pa boost system bugs. [relevant link]
The img/deck column is only a reference number because of grouping and other reasons, the number might vary in different person.


If you feel the above content have any mistakes, or need to be edited. Please feel free to copy the above table and do edition. :sunglasses:

I guess I’d consider PAO a system of only 17, not 52, images. Maybe that’s not what you want to represent with that table though.

Anyway, to me it is one newly composed image per location. Yes with information from three different Ps, As, and Os… but in the end composed into just one new image

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I am not sure how others think, some would say it is actually 52 images, but some says it is only 17. But I can only fill a digit in that box. :upside_down_face: I had changed the subtitle, is it clear now? :wink:


Added a new field ‘undefined card system’. If you have any similar thought please post in here. I will constantly update this table if I encounter any new relevant content.

Actually, it requires 51 images and last 1 card left.
But if you say 17 images that means you consider like this
Every single image is combination of 3 images .

At last you can say that it require 17 images but actually didn’t.

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So how about my system?

I am using single card system , total 52 images (include some person and cartoons too)
I haven’t add action in them.

But I memorize in the group of 2 cards.
So basically it requires only 26 images.

And last 4 cards I memorize in my short term memory.

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Then I might add a remark there, the img/deck is only a reference numbers, bc of grouping and other reasons, they might vary in each person. :smiley: Thanks for your positive feedback.


Could you explain pa-boost system and how it requires 273 images.

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base case: no suit pair = normal PA
case 1: a suited pair happens = an obj used in the same loci → OA
case 2: consecutive suit pair = two objects connected in a loci → OO

The core idea of PA-boost is to make use of ALL PEGS in traditional PAO{300}. Apart from traditional PA {104} pegs, there remains 300-104=196 pegs, take O{100} and create O’{69} = 169 for suit pair cards.

Now, there are 96 pegs, 48 for P, another 48 for A. By finding the most common pattern (prove by logic and simulator), we can convert the remaining pegs as SHORTCUTS!

The prototype is final made after 2-3 weeks of planing and simulations.

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Let’s have a card system pooling, which systems are you using? :flushed:

  • 1 card
  • 2 card
  • 3 card
  • PA
  • PAO
  • PAOX
  • 3S3R
  • 4S2R
  • Others (Please share)

0 voters

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You might want to remove the remove the 3-card option. Obviously, nobody has images for 52*51*50=132,600 card combinations memorized. Even using a block system alongside it, you’d still have to memorize \frac{132,600}{2}=66,300 images.

Just saying, because people new to it always think that they are using a 3-card system with their PAO; when in fact, it’s just a once card system that let’s you build a compound image of three of your pre-memorized images in a particular location.

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I cannot edit it after after the the vote has been updated. :sweat_smile:

Ooops :wink:

Updated the table, and all the thoughts in my mind has already posted in here.
I am grateful to all your votes, your vote can contribute the card memorizing industry in two way. Newcomers: better card system planning. Geniuses: creating a innovative system.
About the update, please refer to this old post. Pusedo2card system (Nov'17) - #14 by Antelex